38. A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are
A. 300 B. 500
C. 800 D. 1000
Answer:
Let their maximum marks be x.
Then, 33% of x = 125 + 40
‹=› 33/100×x= 165
x‹=› (165×100/33)
‹=› 500.
Title : Percentage Q38
Description : 38. A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are ...
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