Solutions (1-5)
1. (2) Here the number of samples in both the years 1986 and 1991 is 1048000
Difference of Percentage:
= (12.1+3+0.8) – (10 + 1.4 + 0.1)
= 15.9 – 11.5 = 4.4
: Required Ans: =4.4% of 1048000
= 4.4x1048000/100 = 4612
2. (1) It is obvious from table.
3. (5) The percentage of low malnourished children shows no increase from the previous one.
4. (4) Req. no. of children = 0.5% of 1071000
=0.5 x 1071000/100 = 5355
5. (2) Req. no. of children = (7.8 + 0.9 + 0.1) % of 1161000
= 8.8 x 1161000/100 = 1,02,168
Solutions (6-10)
6. (4) The increase rate was maximum in 2002
7. (1) We look at the table minutely and calculate the per centage for selective years
i.e. in the year 1999 out of 192, 122 cases were of typhoid, in 2001 out of 144 , 98 cases were of typhoid.
Percentage of typhoid in 1999 = 122 x 100 /192
=63.54%
Percentage of typhoid in 2001 = 98 x 100/144 = 68%
8. (3) Req. number of cases = 86 x 27500000/100000 = 23650
9. (5) Req. rate = 192 – 122 = 70
10. (2) Avg. rate of hepatitis = 27 + 44 + 47 + 86 + 56 + 57 + 39 + 86/8
= 442/8
Avg. rate of typhoid = 46 + 60 + 60 + 109 + 122 + 99 + 98 + 96/8
= 690/8
Req. difference = 690 – 442/8 = 248/8 = 31
