18.Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is
A. 9 B. 11
C. 13 D. 15
Answer:
Let the three integers be x, x+2 and x+4.
Then, 3x = 2(x+4)+3
‹=›x= 11.
Therefore, third integer x+4 = 15.
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