Numbers Q9

9. Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

A.9         B.11

C.13       D.15

Answer: Option D

Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3   

   x = 11.

                        Third integer = x + 4 = 15.