| 59. | The volume of the sphere Q is 3764% less than the volume of sphere P and the volume of sphere R is 1927% less than that of sphere Q. By what % is the surface area of sphere R less than the surface area of sphere P? |
| A. | 77.77 % |
| B. | 87.5 % |
| C. | 75 % |
| D. | 67.5 % |
Answer – (C) Solution: Let the volume of sphere P be 64 parts.
Therefore volume of sphere Q =64−(3764)% of 64=64−37=27 parts. The volume of R =27−(1927)*27=27−19=8 parts. Volume ratio:
=P:Q:R=64:27:8 Radius ratio:
=P:Q:R=4:3:2 The surface area will be 16:9:5
Surface area of R is less than the surface area of sphere P
16k−4k=12k Now, 12k16k*100=75% Thus surface area of sphere R is less than the surface area of sphere P by 75 %
Title : Percentage Q59
Description : 59. The volume of the sphere Q is 3764% less than the volume of sphere P and the volume of sphere R is 1927% less than that of ...
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