69.A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are :
[A] 300
[C] 800
[B] 500
[D] 1000
Answer : [B]
Explanation :
|
|
| Let the maximum marks be x. |
|
|
| Then, 33% of x = 125 + 40 | |
| | x = 165 | | x = |
| |
| = 500. |
| |
Title : Percentage Q69
Description : 69.A student has to obtain 33% of the total marks to pass. He got 125 marks and failed by 40 marks. The maximum marks are : [A] 300 [C] 800 ...
Rating : 5
